If 47.2506=4A+7/B+2C+5/D+6E then the product of A and D is?

Open in App

Solution

4A + 7/B + 2C + 5/D + 6E =47.2506
=> 4 A + 7/B + 2 C + 5/D + 6E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4A =40, 7/B = 7, 2C = 0.2, 5/D = 0.05, 6E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5A + 3B + 6C + D + 3E =(510) + (31) + (60.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003.

Suggest Corrections

Similar questions

47.2506

= 4 A + \frac{7}{B} + 2 C + \frac{5}{D} + 6 E,

5 A + 3 B + 6 C + D + 3 E

$If 47.2506 = 4A + \frac{7}{B} + 2 C + \frac{5}{D} + 6 E, then what is the value of 5A +3B + 6C + D+ 3E?$

\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})

7 \times a + a

6 a^{2} + 7 b + 2 c

4 a \times 3 b \times 2 c

6 (a^{2} + b)

Join BYJU'S Learning Program