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Conversion of Length, Mass and Capacity

If 48 boxes c...

Question

If 48 boxes contain 6000 pens, how many such boxes will be needed for 1875 pens?

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Solution

48 boxes contain 6000 pens.
Number of pens contained in 1 box = $\frac{6000}{48} = 125$ pens.

Therefore, number of boxes needed to contain 1875 pens = $\frac{1875}{125} = 15$ boxes.

Hence, 15 boxes will be needed for 1875 pens.

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