If 486∗7 is divisible by 9, then the least value of ∗ is
(a) 0
(b) 1
(c) 3
(d) 2
The correct option is (d) 2
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
4+8+6+∗+7=25+∗
The next number which is divisible by 9 is 27.
Now, 25+∗=27
∗=27−25=2