Question

If $4a-3=13$, then find the value of $10a^2-5a+6$

Answer 1

Given that

$4a-3=13$

$\Rightarrow 4a=13+3$

$\Rightarrow 4a=16$

$\Rightarrow a=\frac{16}{4}$

$\Rightarrow a=4$

substitute this value of $a$ in the required expression,

$10a^2-5a+6$

$\Rightarrow 10(4{)}^2-5(4)+6$

$\Rightarrow 10\left(16\right)-20+6$

$\Rightarrow 160-20+6$

$\Rightarrow 146$