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Question

If 4qc−6td−3tc+82d is simplified and factorised then its factors are

A
(4q3t)(c+2d)
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B
(4q+3t)(c2d)
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C
(4q3t)(c2d)
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D
(4q+3t)(1+2d)
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Solution

The correct option is A (4q3t)(c+2d)
Let J=4qc6td3tc+8qd

=c(4q3t)+2d(4q3t)

J=(4q3t)(c+2d)

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