Question

If $4x+i(3x-y)=3+i(-6)$ then find the value of $x$ and $y$.

Answer 1

Given,

$4x+i(3x-y)=3+i(-6)$

$4x+i(3x-y)=3-6i$

$4x=3\Rightarrow x=\frac{3}{4}$

$3x-y=-6$

$y=3x+6$

$y=3\times \frac{3}{4}+6\Rightarrow y=\frac{33}{4}$

$\therefore x=\frac{3}{4},y=\frac{33}{4}$