If $4 x + i (3 x - y) = 3 + i (- 6)$ , where $x$ and $y$ are real numbers , then find the value of $x$ and $y$ .

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Solution

Given $4 x + i (3 x - y) = 3 + i (- 6)$
comparing real and imaginary parts of $R . H . S$ and $L . H . S$ , we have,
$4 x = 3 \Rightarrow x = \frac{3}{4}$
$3 x - y = - 6 \Rightarrow 3 \times \frac{3}{4} - y = - 6$

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If 4x+i(3x−y)=3+i(−6), where x and y are real numbers , then find the value of x and y.

Given 4x+i(3x−y)=3+i(−6) comparing real and imaginary parts of R.H.S and L.H.S, we have,4x=3⇒x=343x−y=−6⇒3×34−y=−6

If $4 x + i (3 x - y) = 3 + i (- 6)$ , where $x$ and $y$ are real numbers , then find the value of $x$ and $y$ .

Given $4 x + i (3 x - y) = 3 + i (- 6)$
comparing real and imaginary parts of $R . H . S$ and $L . H . S$ , we have,
$4 x = 3 \Rightarrow x = \frac{3}{4}$
$3 x - y = - 6 \Rightarrow 3 \times \frac{3}{4} - y = - 6$