If (5,12) and (24,7) are the focii of a conic passing through the origin, then the eccentricity of conic is
A
√38612
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B
√38613
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C
√38625
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D
√38638
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Solution
The correct options are A√38612 D√38638 Let the foci be S(5,12) and S′(24,7) The conic passes through the origin. ∴ Let P(0,0) ∴S′P−SP=12 and S′P+SP=38 Distance between focii =2ae √386=2ae If conic is ellipse then S′P+SP=38=2a ∴ Eccentricity e=√38638 And if conic is hyperbola then S′P−SP=12=2a ∴ Eccentricity e=√38612