If $5 = 5, 6 = 12, 7 = 21, 8 = 32$ , then $9$ is equal to

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Solution

Compute the required value
Given that $5 = 5, 6 = 12, 7 = 21, 8 = 32$
Hence the given data can be written as
$5 \times 1 = 5 6 \times 2 = 12 7 \times 3 = 21 8 \times 4 = 32$
so $9 \times 5 = 45$
Hence the value of $9$ is $45$

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Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$