If 5.85 g of NaCl (molecular weight 58.5) is dissolved in water and the solution is made up to 0.5 litre, the molarity of the solution will be

0.2

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0.4

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0.1

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Solution

The correct option is A 0.2
Given:-
Mass of $N a C l ⟶ 5.85 g$
Number of moles of $N a C l = \frac{5.85}{58.5} = 0.1$
Volume $⟶ 0.5$ litre
Molarity= $\frac{N u m b e r o f m o l e s}{V o l u m e (m l)} \times 1000$
$= \frac{0.1}{0.5}$
Molarity= $0.2 M$ .

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