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Question

If α + β = 5 and α3 + β3 = 35, find a quadratic equation whose roots are α and β.

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Solution

We have α+β=5 and α3+β3=35=>(α+β)3-3αβ(α+β)=35=>(5)3-3αβ×5=35=>125-15αβ=35=>15αβ=125-35=90=>αβ=9015=6We know that if α and β are the roots of a quadratic equation, then the quadratic equation is x2-(α+β)x+αβ=0On substituting α+β=5 and αβ=6, we get: x2-5x+6=0

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