Question

If $5$ biscuits are distributed among $3$ beggers, the chance that a particular beggar will ger $2$ biscuits is

Answer 1

No. of biscuits$=5$

No. of beggars$=3$

$5$ biscuits can be distributed away $3$ beggars in the following ways:-

$(2,2,1),(2,1,2),(1,2,2),(3,1,1),(1,3,1),(1,1,3)$

No. of ways $=6$

$1$ beggar will get $2$ biscuits

Possible cases$=(2,2,1),(2,1,2)$ $(1,2,2)$

$=3$ ways

Required Prob $=\frac{3}{6}=\frac{1}{2}$