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Question

If 5cosΘ=3, evaluate : cosecΘcotΘcosecΘ+cotΘ is 1m, m is

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Solution

5cosΘ=3
cosΘ=35
Now, cosecΘcotΘcosecΘ+cotΘ
= 1cosΘ1+cosΘ
= 1351+35
= 535+3
= 28
= 14

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