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B
115
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C
125
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D
100
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Solution
The correct option is A110 Given 5cosθsinθ=1 ⇒5cosθsinθ=sin2θ+cos2θ⇒5=tanθ+cotθ⇒(tanθ+cotθ)3=125⇒tan3θ+cot3θ+3tanθcotθ(tanθ+cotθ)=125⇒tan3θ+cot3θ+3×5=125∴tan3θ+cot3θ=110