Question

If $5\cot \Theta =12$, then the value of : $cosec\Theta +\sec \Theta$ is $m\frac{41}{60}$, where the value of m is

Answer 1

$5\cot \Theta =12$

$\cot \Theta =\frac{12}{5}=\frac{B}{P}$

Using Pythagoras Theorem,

$H^2=P^2+B^2$

$H^2=5^2+{12}^2$

$H=13$

Now, $cosec\Theta +\sec \Theta$

= $\frac{H}{P}+\frac{H}{B}$

= $\frac{13}{5}+\frac{13}{12}$

= $\frac{156+65}{60}$

= $\frac{221}{60}$

= $3\frac{41}{60}$

By comparing we get $m=3$