If 5 molecules of glucose respired aerobically and another 5 molecules anaerobically, what is the total number of ATP and $C O_{2}$ molecules expected form these reactions?

200 ATP and 60 $C O_{2}$

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140 ATP and 40 $C O_{2}$

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200 ATP and 40 $C O_{2}$

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190 ATP and 36 $C O_{2}$

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Solution

The correct option is C
200 ATP and 40 $C O_{2}$

Aerobic respiration released 38 molecules of ATP and 6 molecules of $C O_{2}$ for every Glucose molecule. Therefore if 5 molecules are respired, then it forms $38 \times 5 = 190$
ATPs and $6 \times 5 = 30 C O_{2}$ molecules.

During anaerobic respiration one molecule of glucose releases 2 molecules of ATP and 2 molecules of $C O_{2}$ for one glucose molecule. That is a total of 10 ATPs and 10 $C O_{2}$ molecules. Therefore together we get a total of 190 + 10 = 200 ATP molecules and 30 + 10 = 40 $C O_{2}$ molecules.

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If 5 molecules of glucose respired aerobically and another 5 molecules anaerobically, what is the total number of ATP and CO2 molecules expected form these reactions?

If 5 molecules of glucose respired aerobically and another 5 molecules anaerobically, what is the total number of ATP and $C O_{2}$ molecules expected form these reactions?