Question

If 5 molecules of glucose respired aerobically and another 5 molecules anaerobically, what is the total number of ATP and $C{O}_2$ molecules expected form these reactions?

• A. 200 ATP and 60 $C{O}_2$
• B. 140 ATP and 40 $C{O}_2$
• C. 200 ATP and 40 $C{O}_2$
• D. 190 ATP and 36 $C{O}_2$

Answer 1

The correct option is C

200 ATP and 40 $C{O}_2$

Aerobic respiration released 38 molecules of ATP and 6 molecules of $C{O}_2$ for every Glucose molecule. Therefore if 5 molecules are respired, then it forms $38\times 5=190$
ATPs and $6\times 5=30C{O}_2$ molecules.

During anaerobic respiration one molecule of glucose releases 2 molecules of ATP and 2 molecules of $C{O}_2$ for one glucose molecule. That is a total of 10 ATPs and 10 $C{O}_2$ molecules. Therefore together we get a total of 190 + 10 = 200 ATP molecules and 30 + 10 = 40 $C{O}_2$ molecules.