Question

If $5$ oil tankers can be filled by a pipe in $4hours40minutes$, then:

$15$ such oil tankers can be filled in ______$hours$

Answer 1

Given that,

$5$ oil tankers can be filled by a pipe in $4hours40minutes$

Convert the given time in hour,

We know that,

$1hour=60minutes$

$$\begin{gathered} 4hours40minutes=4hours+\frac{40}{60}hours \\ =(4+\frac{2}{3})hours \\ =\frac{14}{3}hours \end{gathered}$$

Assume, $15$ such oil tankers can be filled $xhours$

In proportion, it can also be written as

$5oil\tan ks:15oil\tan ks::\frac{14}{3}hours:x$

Therefore,

$$\begin{gathered} \frac{5oil\tan ks}{15oil\tan ks}=\frac{{\displaystyle \frac{14}{3}}hours}{x} \\ x=\frac{15\times {\displaystyle \frac{14}{3}}}{5} \\ x=14hours \end{gathered}$$

Hence, $15$ such oil tankers can be filled $14hours$