Question

If $5\sin \theta -7\cos \theta =0$ then find the value of $\sec \theta .$

Answer 1

$5Sin\Theta =7cos\Theta$

$tan\Theta =\frac{7}{5}$

$Sec{\Theta }^2=1+ta{n}^2\Theta =1+\frac{49}{25}=\frac{74}{25}$

$Sec\Theta =\sqrt{\frac{74}{25}}=\frac{\sqrt{74}}{5}$