If 5 tan- - 4- show that 5 sin - - 3 cos -5 sin - - 2 cos - - 16

We have,5 tan α ⇒ tan α = 45 Now, 5 sin α 3 cos α5 sin α + 2 cos α = #160;5 sin α 3 cos αcos α5 sin ...

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Sin2A and Cos2A in Terms of tanA

If 5 tanα =...

Question

If $5 tan α$ = 4, show that $\frac{5 s i n α - 3 c o s α}{5 s i n α + 2 c o s α} = \frac{1}{6}$

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