Question

If $5^{th}$ term of a H.P. is $\frac{1}{45}$ and ${11}^{th}$ term is $\frac{1}{69}$, then its ${16}^{th}$ term will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Here $5^{th}$ term of the corresponding

A.P. = a + 4d = 45 ........(i)

and ${11}^{th}$ term of the corresponding

A.P. = a + 10d =69 .........(ii)

From (i) and (ii), we get a =29, d = 4

Therefore ${16}^{th}$ term of the corresponding A.P.

= a + 15d = 29 + 15$times$4 = 89.

Hence ${16}^{th}$ term of the H.P. is $\frac{1}{89}$