Question

If $50.0$ milliters of $3.50$ M $H_{2}S{O}_4$ be diluted in order to make $2.00$ M $H_{2}S{O}_4$, what should be the final volume in mililiters ?

• A. $25.0$
• B. $60.1$
• C. $87.5$
• D. $93.2$
• E. $101$

Answer 1

The correct option is C $87.5$

$M_1{V}_1=M_2{V}_2$
$M_1=$ 3.50 M $=$ initial molarity
$V_1=$ 50.0 mL $=$ initial volume
$M_2=$2.00 M$=$ final molarity
$V2=$ final volume
$M_1{V}_1=M_2{V}_2$
$3.50\times 50.0=2.00\times V_2$
$V_2=87.5$ mL