If $500$ calorie of heat energy are added to a system and the system does $350$ calorie of work on the surroundings, what is the energy change of the system?

Open in App

Solution

Heat absorbed, $q = 500 c a l$
Work done by the system, $w = - 350 c a l$
Applying the first law of thermodynamics,
$Δ U = q + w = 500 + (- 350) = 150$ calorie

Suggest Corrections

Similar questions

If 500 calorie of heat energy is added to a system and the system does 350 calorie of work is done on surroundings, what is the energy change of the system?

Q. If 500 calorie of heat energy is added to the system and the system does 350 calorie of work on the surroundings, the internal energy change of the system is

Q. If

50

calorie are added to a system and system does work of

30

calorie on surroundings, the change in internal energy of system is ________________.

Q. What is the change in the energy of the system if 500 cal of heat energy is added to a system and system does 350 cal of work on the surroundings?

Q. If

100

calorie of heat are added to the system and a work of

50

calorie is done on the system, calculate the energy change of the system.

Join BYJU'S Learning Program

If 500 calorie of heat energy are added to a system and the system does 350 calorie of work on the surroundings, what is the energy change of the system?

Heat absorbed, q=500calWork done by the system, w=−350calApplying the first law of thermodynamics,ΔU=q+w=500+(−350)=150 calorie

If $500$ calorie of heat energy are added to a system and the system does $350$ calorie of work on the surroundings, what is the energy change of the system?

Heat absorbed, $q = 500 c a l$
Work done by the system, $w = - 350 c a l$
Applying the first law of thermodynamics,
$Δ U = q + w = 500 + (- 350) = 150$ calorie