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Question
If 500 calorie of heat energy is added to a system and the system does 350 calorie of work is done on surroundings, what is the energy change of the system?
If 500 calorie of heat energy is added to a system and the system does 350 calorie of work is done on surroundings, what is the energy change of the system?
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Solution
The correct option is D 150 Calories
The first law of thermodynamics can be given by ΔU = q + w
When q is positive, it is the heat added to the system.
When q is negative, it is the heat taken from the system.
When w is positive, it is the work done on the system.
When w is negative, it is the work done by the system.
Where ′q′ = the heat added to the system and ′w′ = the work done on the system
Heat added to the system = 500 calorie = q
Work done by system = −350 calorie = w
Negative value of work because it is work done by the system
ΔU = q + w = 500 − 350 = 150 calories
The first law of thermodynamics can be given by ΔU = q + w
When q is positive, it is the heat added to the system.
When q is negative, it is the heat taken from the system.
When w is positive, it is the work done on the system.
When w is negative, it is the work done by the system.
Where ′q′ = the heat added to the system and ′w′ = the work done on the system
Heat added to the system = 500 calorie = q
Work done by system = −350 calorie = w
Negative value of work because it is work done by the system
ΔU = q + w = 500 − 350 = 150 calories
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