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Question

If 500e7x+600e7x, show that d2ydx2=49y

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Solution

Given, 500e7x+600e7x
On differentiating w.r.t. x, we get
dydx=7×500e7x7×600e7x
Again differentiating w.r.t. x,
d2ydx2=49×500e7x+49×600e7x
=49(500e7x+600e7x)
=49y

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