Question

If $500J$ of work is required to carry a $40C$charge slowly from one to point another in an electric field, then the potential difference between these two points is

• A. $12.5V$
• B. $20kV$
• C. $0.08V$
• D. Depends upon the path

Answer 1

The correct option is A

$12.5V$

Step 1: Given

$W=500J$ , $Q=40C$ , $V=?$

Step 2: Formula

$V=W/Q$

Step 3: Calculate the value of the potential difference, $V$

$$\begin{gathered} V=W/Q \\ =500/40 \\ =12.5V \end{gathered}$$

The value of potential difference , $V=12.5V$

Final answer:

Thus Option A $12.5V$is correct.