Question

If $500\mathrm{ml}$of a gas A at $1000$ torr and $1000\mathrm{ml}$ of gas B at $800$ torr are placed in $2\mathrm{L}$ a container, the final pressure will be

Answer 1

Step 1: Given Data

The volume of gas A $\left({\mathrm{V}}_{\mathrm{A}}\right)$$=500\mathrm{ml}$

The volume of gas B$\left({\mathrm{V}}_{\mathrm{B}}\right)=1000\mathrm{ml}$

The pressure of gas A$\left({\mathrm{P}}_{\mathrm{A}}\right)=1000\mathrm{torr}$

The pressure of gas B$\left({\mathrm{P}}_{\mathrm{B}}\right)=800\mathrm{torr}$

Total volume$=$volume of the container$=$$2000\mathrm{ml}$

Step 2:Applying pressure formula

${\mathrm{P}}_{\mathrm{Total}}=\frac{{\mathrm{P}}_{\mathrm{A}}{\mathrm{V}}_{\mathrm{A}}+{\mathrm{P}}_{\mathrm{B}}{\mathrm{V}}_{\mathrm{B}}}{{\mathrm{V}}_{\mathrm{Total}}}$

${\mathrm{P}}_{\mathrm{Total}}=\frac{1000\times 500+800\times 1000}{2000}$

${\mathrm{P}}_{\mathrm{Total}}=\frac{1300000}{2000}\Rightarrow \frac{1300}{2}\Rightarrow 650\mathrm{torr}$

Therefore, total pressure$=650\mathrm{torr}$