If (5,12) and (24,7) are the foci of a conic passing through the origin, then the eccentricity of conic can be:
A
√38612
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B
√38638
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C
√38613
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D
√38625
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Solution
The correct option is B√38638 Let S(5,12) and S′(24,7) be the two foci of the conic.
It passes through P(0,0) ⇒SP=√52+122=13 ⇒S′P=√242+72=25 ⇒SS′=√192+52=√386
If the conic is ellipse, then SP+S′P=2a and SS′=2ae ∴e=SS′SP+S′P=√38638
If the conic is hyperbola, then |SP−S′P|=2a and SS′=2ae ∴e=√38612