Question

If $5432\ast 7,9$ is divisible by $9$, then the digit in place of * is :

• A. $0$
• B. $1$
• C. $6$
• D. $9$

Answer 1

Answer: (C)

$6$

For divisibility by 9, sum of digits should be divisible by 9

Now, sum of digits of $5432\ast 7$ is $5+4+3+2+x+7=21+x$

When $x=0,S=21$ (not divisible by $9$)

When $x=1,S=22$ (not divisible by $9$)

When $x=6,S=27$ (divisible by $9$)

When $x=9,S=30$ (not divisible by $9$)

$\Rightarrow \left(C\right)$