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Question

If 5Cr=r 5Cr1, then the number of value(s) of r is

A
2
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B
1
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C
0
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D
3
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Solution

The correct option is B 1
Given : 5Cr=r 5Cr1
5Cr 5Cr1=r
5r+1r=r (since nCr nCr1=nr+1r)

r2+r6=0
(r+3)(r2)=0
r=3,2
rejecting r=3 as rW
Number of solution =1

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