Consider the given equation,
5x−2y=7 and xy=2
We have to find (5x+2y)2=?
Now,
(5x−2y)2=25x2+4y2−20xy
72=25x2+4y2−20×2
25x2+4y2=89
(5x+2y)2=25x2+4y2−20xy
(5x+2y)2=89−20×2
(5x+2y)2=49
Hence, this is the answer.
If 5x−2y=7 and xy=2 , then find the value of (5x+2y)2
5x−2y=7 and xy=2, find the value of (5x+2y)2
Factorise : 2(x+2y)2−5(x+2y)+2
If x : y = 4 : 7, Find the value of (3x+ 2y) : (5x + y).