If 5^x-3×3^2x-8= 225

Then, x=?

Open in App

Solution

5^x-3. 3^2x-8 = 225
= 3 × 75
= 3 × 3 × 25
= 3 × 3 × 5 × 5
∴ 5^x-3. 3^2x-8= 5² × 3²
Comparing both the sides we get
x − 3 = 2
⇒ x = 5 (You can compare even the other one also. The result will be same)

Suggest Corrections

233

Similar questions

x,

5^{x - 3} \times 3^{2 x - 8} = 225

5^{x - 3} \times 3^{2 x - 8} = 225

2^{x - 3} \times 3^{2 x - 8} = 36

x

$2 x^{2} + 5 x + 3 = ? (a) (x + 3) (2 x + 1) (b) (x + 1) (2 x + 3) (c) (2 x + 5) (x - 3) (d) n o n e o f t h e s e$

\sqrt[5]{5 x + 2} = 2

\sqrt[3]{3 x - 2} = 4

{(\frac{3}{4})}^{3} {(\frac{4}{3})}^{- 7} = {(\frac{3}{4})}^{2 x}

5^{x - 3} \times 3^{2 x - 8} = 225

\frac{3^{3 x} \cdot 3^{2 x}}{3^{x}} = \sqrt[4]{3^{20}}

Join BYJU'S Learning Program