Question

If $6.3g$ of $NaHC{O}_3$ are added to $10g$ of HCl solution, the residue is found to weigh $12g$. What is the mass of $C{O}_2$ released in the reaction?

• A. $43g$
• B. $21.5g$
• C. $50g$
• D. $4.3g$

Answer 1

The correct option is D $4.3g$

$NaHC{O}_3+HCl\to Residue+C{O}_2$
Weight of reactants = weight of $NaHC{O}_3$+weight of HCl
$=6.3+10=16.3g$
Weight of product = weight of residue+weight of $C{O}_2$
$=12+x$
$x\to$weight of $C{O}_2$ released.
a/c to law of conservation of mass
Weight of reactants = weight of products
$16.3=12+x$
$\Rightarrow x=16.3-12=4.3$
Weight of $C{O}_2$ released $=4.3g$