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Volume of Gases and Number of Moles

If 6.3 g of...

Question

If $6.3 g$ of $N a H C O_{3}$ are added to $10 g$ of HCl solution, the residue is found to weigh $12 g$ . What is the mass of $C O_{2}$ released in the reaction?

43 g

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21.5 g

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50 g

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4.3 g

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Solution

The correct option is D $4.3 g$
$N a H C O_{3} + H C l \to R e s i d u e + C O_{2}$
Weight of reactants = weight of $N a H C O_{3}$ +weight of HCl
$= 6.3 + 10 = 16.3 g$
Weight of product = weight of residue+weight of $C O_{2}$
$= 12 + x$
$x \to$ weight of $C O_{2}$ released.
a/c to law of conservation of mass
Weight of reactants = weight of products
$16.3 = 12 + x$
$\Rightarrow x = 16.3 - 12 = 4.3$
Weight of $C O_{2}$ released $= 4.3 g$

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