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Question

If 6.539×102g of metallic zinc is added to 100 ml saturated solution of AgCl. Find the value of log10[Zn2+][Ag+]2.

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Solution

According to the problem:-
2Ag++2e2Ag;(E=0.80v) Since,(65.39×10265.39=103molesofznhasbeenadded)
ZnZn2++2e;(E=0.80v)
Hence,

2Ag+(aq)+Zn(s)Zn2+(eq)+2A(s);E=1.57v

log10K(eq)=52.8
Therefore, if the reaction will move in the forward direction completely. Hence moles of Ag formed will be 106
(At Equilibrium Ece11=0)

Ece11=+0.05912log10[Zn+2][Ag+]2
Hence,
1.56×20.0591=log[Zn+2][Ag+2]2=52.8

Hence the answer is 52.8

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