Question

If 6, 8 and c form a Pythagorean triplet, then find the value of c?

• A. 4
• B. 5
• C. 7
• D. 10

Answer 1

The correct option is D

10

$\text{We know that,}2m,m^2-1\text{and}{m}^2+1\text{form a Pythagorean triplet.}$

$\text{Let us consider}2m=6\Rightarrow m=3.\text{Then,}(m^2–1)=9-1=8$

$\text{Hence,}c=m^2+1$
$\therefore c=(m^2+1)=9+1=10$

$\text{6, 8, 10 form a Pythagorean triplet.}$