If 6 -2 cosec-5 cosec- then cos- is-

The correct option is D nbsp; ...

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Standard Values of Trigonometric Ratios

If 6 θ+2 cose...

Question

If 6 cotθ + 2 cosecθ = cotθ + 5 cosecθ, then cosθ is:

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(i) \sqrt{\frac{1 + \sin θ}{1 - \sin θ}} = (\sec θ + \tan θ) (ii) \sqrt{\frac{1 - \cos θ}{1 + \cos θ}} = (cosec θ - \cot θ) (iii) \sqrt{\frac{1 + \cos θ}{1 - \cos θ}} + \sqrt{\frac{1 - \cos θ}{1 + \cos θ}} = 2 cosec θ

If $3 tan θ + cot θ = 5 c o s e c θ$ , then $θ =$ __ (in degrees) [ $0^{\circ} < θ < 90^{\circ}$ ]

sin θ, cos θ

tan θ

{cot}^{6} θ - {cot}^{2} θ

\frac{sin θ}{1 + cos θ} + \frac{1 + cos θ}{sin θ} = 2 c o s e c θ

\sqrt{\frac{1 + c o s θ}{1 - c o s θ}} + \sqrt{\frac{1 - c o s θ}{1 + c o s θ}} = 2 c o s e c θ

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