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Question

If 6 moles of Cu reacted according to the following reaction equation Cu(s)+HNO3(aq)Cu(NO3)2(aq)+H2O(l)+NO(g), and is balanced, what will be the number of moles of NO that would be formed?

A
1
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B
2
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C
3
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D
4
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E
5
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Solution

The correct option is E 4
The unbalanced chemical equation is
Cu(s)+HNO3(aq)Cu(NO3)2(aq)+H2O(l)+NO(g)
Cu atoms are balanced.
Balance N atoms.
Cu(s)+3HNO3(aq)Cu(NO3)2(aq)+H2O(l)+NO(g)
The oxidation number of Cu increases from 0 to +2.
Total increase in the oxidation number = 2.
The oxidation number of N decreases from +5 to +2.
Total decrease in the oxidation number of N is 3.
Balance increase in the oxidation number with decrease in oxidation number.
3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+H2O(l)+2NO(g)
Balance O atoms.
3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+4H2O(l)+2NO(g)
H atoms are already balanced.
3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+4H2O(l)+2NO(g)
This is the balanced chemical equation.
If 6 moles of Cu reacted according to the above reaction, 2×63=4 moles of NO would be formed.

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