If 6 moles of Cu reacted according to the following reaction equation Cus-HNO3aq- CuNO32aq-H2Ol-NOg- and is balanced- what will be the number of moles of NO that would be formed-

The correct option is E 4 The unbalanced chemical equation is #160; Cu(s)+HNO_3(aq)→ Cu(NO_3)_2(aq)+H_2O(l)+NO(g) Cu atoms are balanced. Balance N a ...

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Byju's Answer

Standard IX

Chemistry

Balancing Chemical Equations by Partial Equation Method

If 6 moles ...

Question

If $6$ moles of Cu reacted according to the following reaction equation $C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$ , and is balanced, what will be the number of moles of NO that would be formed?

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Solution

The correct option is E $4$
The unbalanced chemical equation is
$C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$
Cu atoms are balanced.
Balance N atoms.
$C u (s) + 3 H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$
The oxidation number of Cu increases from 0 to +2.
Total increase in the oxidation number = 2.
The oxidation number of N decreases from +5 to +2.
Total decrease in the oxidation number of N is 3.
Balance increase in the oxidation number with decrease in oxidation number.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + H_{2} O (l) + 2 N O (g)$
Balance O atoms.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + 4 H_{2} O (l) + 2 N O (g)$
H atoms are already balanced.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + 4 H_{2} O (l) + 2 N O (g)$
This is the balanced chemical equation.
If 6 moles of Cu reacted according to the above reaction, $2 \times \frac{6}{3} = 4$ moles of NO would be formed.

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Similar questions

Q. When the following equation:

C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)

is balanced, what will be the coefficient of

C u

, in the lowest whole number?

C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)

C u (N O_{3})_{2}

goes into solution as ions, find the number of ions into which it will dissociate?

Zinc reacts with CuSO4 according to the equation

$Z n + C u S O_{4 \to} Z N S O_{4} + C u$ . If excess of zinc is

added to 100.0 ml of 0.05M CuSO $_{4}$ , the amount

of copper formed in moles will be :

1

mole of

N O

and

1

mole of

O_{3}

are taken in

10 L

vessel and heated. At equilibrium,

50 %

N O

(by mass) reacts with

O_{3}

according to the equation:

N O (g) + O_{3 (g)} ⇌ N O_{2 (g)} + O_{2 (g)}

What will be the equilibrium constant for this reaction?

2

g of brass containing Cu and Zn only reacts with

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solution. Following are the reactions taking place:

C u (s) + H N O_{3} (a q) \to C u^{2 +} (a q) + N O_{2} (g) + H_{2} O (l)

Z n (s) + H^{+} (a q) + N O_{3}^{-} (a q) \to N H_{4}^{+} (a q) + Z n^{2 +} (a q) + H_{2} O (l)

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N O_{2} (g)

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1.04

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atm

[C u = 63.5, Z n = 65.4]

The percentage by mass of Cu in brass was?

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If 6 moles of Cu reacted according to the following reaction equation Cu(s)+HNO3(aq)→Cu(NO3)2(aq)+H2O(l)+NO(g), and is balanced, what will be the number of moles of NO that would be formed?

If $6$ moles of Cu reacted according to the following reaction equation $C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$ , and is balanced, what will be the number of moles of NO that would be formed?