If $60, 82$ and $126$ , are each divided by a number then the reminder is the same in each case. The greatest possible value of the divisor is

16

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22

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Solution

The correct option is C $22$
Since the remainder is same in each case the
difference of every pair of the given numbers
would be exactly divisible by the required number
Now $82 - 60 = 22, 126 - 82 = 44, 126 - 60 = 66$
$∴$ Required number $= H C F o f 22, 44 a n d 66 = 22$

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If 60,82 and 126, are each divided by a number then the reminder is the same in each case. The greatest possible value of the divisor is

The correct option is C 22Since the remainder is same in each case thedifference of every pair of the given numberswould be exactly divisible by the required numberNow 82−60=22,126−82=44,126−60=66∴ Required number =HCF of 22,44 and 66=22

If $60, 82$ and $126$ , are each divided by a number then the reminder is the same in each case. The greatest possible value of the divisor is

The correct option is C $22$
Since the remainder is same in each case the
difference of every pair of the given numbers
would be exactly divisible by the required number
Now $82 - 60 = 22, 126 - 82 = 44, 126 - 60 = 66$
$∴$ Required number $= H C F o f 22, 44 a n d 66 = 22$