Question

If $63.3605=6A+\frac{3}{B}+3C+\frac{6}{D}+5E$, then what is the value of $4A+7B+6C+D+3E$.

• A. $47.603$
• B. $4.7603$
• C. $147.6003$
• D. $47.6003$

Answer 1

The correct option is C $147.6003$

$63.3605=6\times 10+3\times 1+3\times \frac{1}{10}+6\times \frac{1}{100}+0\times \frac{1}{1000}+5\times \frac{1}{10000}$
$=6A+\frac{3}{B}+3C+\frac{6}{D}+5E$
$\Rightarrow A=10,B=1,C=\frac{1}{10},D=100,E=\frac{1}{10000}$
$\therefore 4A+7B+6C+D+3E$
$=4\times 10+7\times 1+6\times \frac{1}{10}+100+3\times \frac{1}{10000}$
$=40+7+0.6+100+0.0003$
$=147.6003$