Question

If $63kcal$ of heat is needed to melt $10kg$ of lead at its melting point, what is the latent heat of fusion of lead ?

Answer 1

Step 1: Given Data

Heat Energy = $63kcal$

Mass = $10kg$

Step 2: Formula used

Mass m, the quantity of heat Q, and latent heat L are related as follows

$Q=mL$

Step 3: Calculation of latent heat of fusion

$$\begin{gathered} Q=mL \\ L=\frac{Q}{m} \end{gathered}$$

$L=\frac{63}{10}$= $6.3Kcal/kg$

Hence, $6.3kcal/kg$is the latent heat of fusion of lead.