Question

If 68y5 is divisible by 11,Where y is a digit,What is the value of y

Answer 1

If a no is divisible by 11.
Sum its odd digits-a
Sum its even digits-b
a-b is divisible by 11.
so in your case sum of odd digits is 6+y
Sum of even digits is 13
So subtracting sum of odd digits and even digits u get a number which is divisible by 11.
so subtracting above two you will get
(6+y)-13=y-7
and that will be equal to a number divisible by 11 so let it be 11x where x is any integer.
so y-7=11x
y=11x+7
put x=0
so y=7