Question

If 6a² – 15b² = ab, where a and b are positive integers, then the value of $\frac{8a^3}{b^3}-\frac{125b^3}{a^3}$ is

यदि 6a² – 15b² = ab, जहाँ a व b धनात्मक पूर्णांक हैं, तब $\frac{8a^3}{b^3}-\frac{125b^3}{a^3}$ का मान है

• A. $\frac{191}{27}$
  
• B. $\frac{271}{27}$
  
• C. $\frac{291}{27}$
  
• D. $\frac{302}{27}$
  

Answer 1

The correct option is B $\frac{271}{27}$


Solution