Question

If $6m^2+\frac{2}{m^2}=7$, then $m=\pm \sqrt{\frac{2}{3}},\pm \frac{1}{\sqrt{2}}$.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is A Yes

Given equation is:

$6m^2+\frac{2}{m^2}$

$\therefore 6m^4-7m^2+2=0$
$6m^4-3m^2-4m^2+2=0$
$(3m^2-2)(2m^2-1)=0$

$\therefore m=\pm \frac{\sqrt{2}}{\sqrt{3}},\pm \frac{1}{\sqrt{2}}$