If $6 x - 1, 4 x + 7$ and $6 x$ are in A.P then the value of $x$ is

2

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\frac{3}{2}

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\frac{5}{2}

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\frac{15}{4}

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Solution

The correct option is C $\frac{3}{2}$
$6 x - 1, 4 x + 7$ and $6 x$ are in A.P
$∴ 2 (4 x + 7) = 6 x - 1 + 6 x$
$\Rightarrow 8 x + 14 = 12 x - 1$
$\Rightarrow 4 x = 15$
$\Rightarrow x = \frac{15}{4}$
$∴$ Option D is correct.

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