If 7 3 - 343 then - 343 -

The correct option is C 7 [ We have; 7^ 3 =343; ...

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Standard VIII

Mathematics

Indices in Rational Form

If 7 3 = 3...

Question

If $7^{3} = 343$ then $\sqrt[3]{343} = ?$

9

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7^{3}

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7

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Solution

The correct option is C $7$
$\begin{matrix} W e h a v e 7^{3} = 343 n o w, \sqrt[3]{343} = \sqrt[3]{{(7)}^{3}} = 7 h e n c e, t h e o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$

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Similar questions

Q. If

7^{3} = 343

then

\sqrt[3]{343} = ?

Simplify:

(i) $(16^{\frac{- 1}{5}})^{\frac{5}{2}}$

(ii) $\sqrt[5]{(32)^{- 3}}$

(iii) $\sqrt[3]{(343)^{- 2}}$

(iv) $(0.001)^{\frac{1}{3}}$

(v) $\frac{(25)^{\frac{3}{2}} \times (243)^{\frac{3}{5}}}{(16)^{\frac{5}{4}} \times (8)^{\frac{4}{3}}}$

(vi) ${(\frac{\sqrt{2}}{5})}^{8} \div {(\frac{\sqrt{2}}{5})}^{13}$

(vii) ${(\frac{5^{- 1} \times 7^{2}}{5^{2} \times 7^{- 4}})}^{\frac{7}{2}} \times {(\frac{5^{- 2} \times 7^{3}}{5^{3} \times 7^{- 5}})}^{\frac{- 5}{2}}$

Q. Show that

l o g \frac{162}{343} + 2 l o g \frac{7}{9} - l o g \frac{1}{7} = l o g 2

What is the value of $n$ if $343^{\frac{n}{3}} \times 7^{5 + 3 n} \times 7^{- 2 n} \times 49^{n - 1} = 343$ ?

Q. Prove

log \frac{162}{343} + 2 log \frac{7}{9} - log \frac{1}{7} = log 2

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If 73=343 then 3√343=?

The correct option is C 7Wehave73=343now,3√343=3√(7)3=7hence,theoptionCisthecorrectanswer.

If $7^{3} = 343$ then $\sqrt[3]{343} = ?$

The correct option is C $7$
$\begin{matrix} W e h a v e 7^{3} = 343 n o w, \sqrt[3]{343} = \sqrt[3]{{(7)}^{3}} = 7 h e n c e, t h e o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$