If 7 sin2θ+3cos2θ=4, then sec θ+cosec θ is equal to
2√3−2
2√3+2
2√3
None of these
7sin2θ+3cos2θ=4⇒7sin2θ+3(1−sin2θ)=4[∵cos2θ+sin2θ=1]⇒7sin2θ+3−3sin2θ=4⇒4sin2θ=1⇒sin2θ=14⇒sinθ=12∴θ=30∘ We have, sec 30∘=2√3 and cosec 30∘=2∴sec 30∘+cosec 30∘=2√3+2
If 7 sin2θ+3cos2θ=4, then secθ+cosecθ is equal to
If 7sin2θ+3cos2θ=4, then secθ+cosecθ is equal to
if 5 cot θ = 4, then find the value of (2 sin2θ + 3 cos2θ) / (7 sin θ . cos θ).