If 7 sin 2-3 cos 2-4- show that tan -13

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Calculating Heights and Distances

If 7 sin 2θ+3...

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If 7 sin² θ + 3 cos²θ = 4, show that tan θ = $\frac{1}{\sqrt{3}}$

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3 {cos}^{2} θ + 7 {sin}^{2} θ = 4

cot θ = \sqrt{3}

\sqrt{3}

\frac{1}{\sqrt{3}}

\sqrt{3}

θ = \frac{8}{15}, evaluate \frac{(2 + 2 sinθ) (1 - sinθ)}{(1 + cosθ) (2 - 2 cosθ)} .

7 {sin}^{2} θ + 3 {cos}^{2} θ = 4

tan θ

θ

7 {sin}^{2} θ + 3 {cos}^{2} θ = 4

tan θ = \frac{1}{\sqrt{3}}

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