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Question

If 7th and 13th terms of an AP be 34 and 64, then its 18th and 25th term is :

A
87
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B
88
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C
89
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D
90
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Solution

The correct options are
C 89
D 90
an=a+(n1)da+6d=34(1)a+12d=64(2)Solving (1) and (2),a=4 and d=5a18=4+(17)5=89
Similarly 25th term is,
a_{25} = 4+(24)5=124\)


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