Question

If 735 is divisible by , 5 and (ascending order) then it is also divisible by 15, 21 and 105.

• A. 3
• B. 4
• C. 7
• D. 2

Answer 1

Answer: (A), (C)

7

We know that 3, 5 and 7 are relatively prime numbers because they don't have any factor other than 1 common between them.

If 735 is divisible by 3 and 5, then, it is also divisible by 15 ($\because$ 15 = $3\times 5$)

If 735 is divisible by 3 and 7, then, it is also divisible by 21 ($\because$ 21 = $3\times 7$)

If 735 is divisible by 3, 5 and 7, then, it is also divisible by 105 ($\because$ 105 = $3\times 5\times 7$)